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MODULE 6 · UNIT 2 OF 5

Buckling Load and Critical Speed

approx. 8 min · Learning goals, example, knowledge check

Learning goals — after this unit, you will be able to …

  • calculate the Euler buckling load of a ball screw for a given bearing arrangement;
  • calculate the critical speed (bending resonance) and use it to determine the permissible operating speed;
  • Distinguish between the four types of bearing arrangements (fixed-fixed, fixed–pinned, articulated-articulated, fixed-free) and their buckling length conventions.

Two stability limits instead of a single moment analysis

A long, high-speed ball screw rarely fails due to drive torque. It fails due to stability: Under compressive load, it can buckle, and at high speeds, it enters bending resonance. Both limits depend on the same parameter—the unsupported length L between the bearings—and the relationship is quadratic: Doubling L reduces the buckling load by a factor of four.

Euler buckling load

The theoretical buckling load follows the Euler method; F_k/S is permissible. For ball screws, S ≥ 2 is the standard rule of thumb listed in catalogs; higher values apply where there is a risk to personnel—the manufacturer’s specifications are binding. The moment of inertia I depends on the fourth power of the core diameter d_r —a diameter of 16 mm instead of 14 mm already results in approximately 70% higher buckling load:

I = π · d_r⁴ / 64

F_k = n_L · π² · E · I / L²

F_k = Buckling load (N) · E = 210,000 N/mm² (steel) · d_r = Core diameter (mm) · L = unsupported length between bearings (mm) · n_L = Bearing coefficient. Catalogs sometimes approximate d_r as the nominal diameter minus the ball diameter.

Validity: Euler’s formula applies only to slender spindles. The slenderness ratio is defined as λ = L / (√n_L · d_r/4); Euler’s formula applies only above the critical slenderness ratio (empirical value for steel is approximately 90–105; use the higher value when in doubt). For short, stocky spindles, the manufacturer’s buckling diagram applies. Second limit: Regardless of the buckling load, the allowable compressive stress of the spindle as well as the load ratings of the nut and fixed bearing limit the axial force—the smallest value is decisive.

Bearing Types and Their Coefficients

The bearing arrangement is fully reflected in the coefficient n_L —ranging from 0.25 (fixed–free) to 4 (fixed–fixed), representing a factor of 16 between the worst and best arrangements. The decisive factor here is how strongly a bearing clamps the spindle end against tilting—these are bending boundary conditions, not the question of whether the bearing holds the spindle axially in place. The same system provides the speed coefficient f_n for the critical speed:

  • Fixed–fixed (both ends supported, e.g., a pair of angular contact ball bearings): n_L = 4 · f_n = 27.6
  • Fixed–pinned (one fixed bearing, one floating bearing): n_L = 2 · f_n = 19.0
  • Articulated–Articulated (both ends mounted with tilting motion): n_L = 1 · f_n = 12.2
  • Fixed–Free (one end fixed, the other free): n_L = 0.25 · f_n = 4.3
Fixed–pinned bearingOne end of the shaft is rigidly clamped, the other is mounted in a hinged bearing—bearing coefficient n_L= 2.
Articulated-to-articulated bearing arrangementBoth shaft ends are mounted on articulated bearings—bearing coefficient n_L= 1.
Fixed–floating bearing arrangementOne shaft end is rigidly clamped, the other is free (floating)—bearing support ratio n_L=0.25; this is the least favorable bearing arrangement.

Critical speed

At high rotational speeds, the spindle enters bending resonance. The critical speed n_krit is the speed at which this resonance begins; 80% of this value is considered permissible:

n_krit = f_n · (d_r / L²) · 10⁷

n_zul = 0.8 · n_krit

n_krit, n_zul in min⁻¹ · d_r, L in mm (numerical-value equation, coefficients for steel: E = 210,000 N/mm², ρ = 7.85 kg/dm³). In addition, the speed parameter of the nut (d₀ · n) limits the speed – the smaller value applies. Caution when comparing with catalogs: some already include the factor 0.8 in the coefficient (then about 9.7 / 15.1 / 21.9 / 3.4) and give n_zul directly – do not multiply by 0.8 again.

Ball screw catalogs specify a maximum axial force of 50% of the buckling load (safety factor S = 2)—a standard rule of thumb for ball screws; this value is higher when there is a risk to personnel, and the manufacturer’s specifications are binding. The ball screw calculator is preset with the stricter value S = 2.5. Screw jack manufacturers often calculate a buckling safety factor of 3 for the lead screw; here, too, the manufacturer’s specifications are binding.

Important Note

L is the bearing distance—the unsupported length between the bearings or from the fixed bearing to the free end—not the Euler buckling length β·L. The bearing arrangement is already fully accounted for in the coefficient n_L; anyone who additionally uses the Euler buckling length is counting it twice. Manufacturers sometimes use the length over which the compressive force acts (from the nut to the fixed bearing in the most unfavorable position) as the buckling load; the bearing spacing is chosen on the safe side.

Worked example

Given

Core diameter d_r = 15 mm, bearing spacing L = 800 mm, fixed–pinned bearing arrangement (n_L = 2, f_n = 19.0).

Calculation

  • I = π · 15⁴ / 64 ≈ 2,485 mm⁴
  • F_k = 2 · π² · 210,000 · 2,485 / 800² ≈ 16,095 N → acceptable (S = 2): F_zul ≈ 8,048 N
  • Slenderness λ = 800 / (√2 · 15/4) ≈ 151 – well above the critical slenderness ratio; Euler’s formula applies
  • n_krit = 19.0 · (15 / 800²) · 10⁷ ≈ 4,453 min⁻¹ → n_zul = 0.8 · 4,453 ≈ 3,562 min⁻¹

For verification: Ball screw calculator (opens in a new tab)

  • Marked point 1: Example: 16,095 N
  • Marked point 1: Example: 16,095 N
Figure 6.2-1: Euler buckling load versus bearing spacing, four bearing arrangements. Source: Calculation Method for This Learning Unit
Description and values of the figure

All four curves apply to a core diameter d_r = 15 mm and a bearing spacing L ranging from 800 to 1,600 mm, and they vary with the square of L. In this range, the slenderness ratio of all points is 107 or higher—the spindle is slender, and Euler’s formula applies. Fixed-Fixed (bearing coefficient 4) withstands the highest load, while Fixed-Free (bearing coefficient 0.25) withstands the lowest. The highlighted Fixed–pinned curve corresponds to the bearing configuration in the worked example for this unit (L = 800 mm, 16,095 N). The dashed line shows the allowable load F_zul=F_k/2 with a safety factor S=2 (standard rule of thumb in the catalog; the linked online calculator uses S=2.5 by default—this is not a contradiction, just a different standard value). The dashed line coincides with the “Hinge-Hinge” curve (2/2 = 1).

Buckling load F_k by bearing type and bearing spacing
Bearing spacing L (mm)Fest–Fest (n_L=4) (N)Fest–Gelenkig (n_L=2) (N)Gelenkig–Gelenkig (n_L=1) (N)Fest–Frei (n_L=0,25) (N)F_zul = F_k/2 (S=2, bezogen auf Fest-Gelenkig) (N)
800 32,19116,0958,0482,0128,048
1,000 20,60210,3015,1511,2885,151
1,200 14,3077,1543,5778943,577
1,400 10,5115,2562,6286572,628
1,600 8,0484,0242,0125032,012

Knowledge check

Answer all three questions, then click "Check". From 2 of 3 correct answers, the unit counts as completed. You can retry at any time.

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Question 1 of 3: How is the moment of inertia I of a spindle with a core diameter of d_r calculated?
Explanation

I = π · d_r⁴/64 is the moment of inertia of a solid circular cross-section—it is a factor in both the Euler buckling load and the critical speed.

Source: Ball Screws: Selection and Design →
Question 2 of 3: What percentage of the critical speed n_krit is considered the permissible operating speed n_zul?
Explanation

n_zul = 0.8 · n_krit – the operating speed should not exceed 80% of the critical (bending resonance) speed.

Source: Ball Screws: Selection and Design →
Question 3 of 3: A spindle with a core diameter of d_r = 16 mm and a bearing spacing of L = 1,000 mm is mounted with a fixed-fixed bearing arrangement (n_L = 4). What is the Euler buckling load F_k in N (E = 210,000 N/mm²)?
N
Explanation

I = π · 16⁴ / 64 ≈ 3,217 mm⁴. F_k = n_L · π² · E · I / L² = 4 · π² · 210,000 · 3,217 / 1,000² ≈ 26,670 N (slenderness ratio λ = 1,000 / (2 · 4) = 125 – Euler’s formula applies).

Source: Ball Screw Calculator →

Please answer all three questions to activate "Check".

Further reading (optional)

Online Calculator: Ball Screw Calculator (opens in a new tab) Guide: Ball Screws—Selection and Design (opens in a new tab)

Learning purpose: calculation methods and figures are simplified teaching examples. For a real machine, the manufacturer’s specifications, the relevant standards and a check by a qualified person apply.

Curriculum v0.1 (Beta) · Status 17.09.2026 · content carefully prepared and reviewed – final sign-off to follow

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