Beta – TEA Academy is new. The content is for learning; it has been prepared with care but has not yet been technically approved. It does not replace design based on the manufacturer’s specifications. Found an error? Write to us.

← Back to Module Overview
MODULE 4 · UNIT 3 OF 5

Spur or Helical Gearing

approx. 7 min · Learning goals, example, knowledge check

Learning goals — after this unit, you will be able to …

  • Distinguish between straight and helical gearing based on smoothness of operation, load capacity, axial force, and efficiency;
  • calculate the forces acting on helical gearing (circumferential, axial, and radial forces);
  • Use a requirements profile to explain when helical gearing is preferable to spur gearing.

Two tooth profiles, two operating characteristics

In spur gearing, the teeth run parallel to the gear axis. Mesh engagement begins and ends abruptly across the entire tooth width—this generates periodic impacts and noise and limits the load-carrying capacity to the profile overlap alone.

In helical gearing, the teeth are inclined relative to the axis by the helix angle β (typically 8–20°). As a result, the contact moves smoothly across the tooth width: the force is gently applied and dissipated, which makes the operation significantly smoother. In addition to the profile overlap ε_α, there is also the jump overlap ε_β—the total overlap ε_γ = ε_α + ε_β increases, and on average, more teeth are in contact at the same time.

Spur gearingA pair of spur gears with spur gearing; the axes are parallel.
Helical gearingA pair of spur gears with helical gearing and parallel axes; the teeth of the two gears are inclined in opposite directions.

Forces on Helical Gearing

The inclined tooth line decomposes the tooth force into three components. The torque M and the pitch diameter d give rise to circumferential, axial, and radial forces:

F_t = 2 · M / d

F_a = F_t · tan β

F_r = F_t · tanα_n/cos β

F_t = Circumferential force (N) · F_a = Axial force (N) · F_r = Radial force (N) · M = Torque (Nmm) · d = Pitch diameter (mm) · β = Helix angle · α_n = Normal pressure angle (usually 20°)

The shaft bearing must reliably absorb this axial force—often, a simple deep groove ball bearing is no longer sufficient for this purpose, and angular contact ball bearings or tapered roller bearings are required.

Direct Comparison

A Direct Comparison of Spur Gearing and Helical Gearing
Characteristic Spur gearing Helical gearing
Smooth Operation / Noiseloud (sudden engagement)significantly quieter (sliding engagement)
Load capacityStandardbis ca. +30 %
Axial forcekeinevorhanden
Efficiencyvery highslightly lower
Manufacturing / Costssimple, affordablemore complex

The special type known as arrow-tooth gearing (double helical gearing) combines two mirror-image halves on a single gear—the axial forces cancel each other out, resulting in smooth operation and high load-carrying capacity without axial bearing load, although the manufacturing process is more complex.

Mnemonic

Spur gearing is simple, inexpensive, and produces no axial force—ideal for slow, non-critical drives. Helical gearing runs more quietly, can handle up to approximately 30% more load, and is suitable for high load/speed applications—but it generates an axial force that the bearings must absorb.

Worked example

Given

A helical spur gear transmits M = 150 Nm with a pitch circle diameter d = 80 mm, helix angle β = 12°, and normal mesh angle α_n = 20°.

Calculation

  • Circumferential force: F_t = 2 · M / d = 2 · 150,000 Nmm / 80 mm = 3,750 N
  • Axial force: F_a = F_t · tan 12° = 3,750 · 0.2126 ≈ 797 N
  • Radial force: F_r = F_t · tan 20° / cos 12° = 3,750 · 0.3640 / 0.9781 ≈ 1,395 N

The axial force here corresponds to approximately 21% of the circumferential force—a value that must be taken into account from the very beginning when selecting bearings.

Figure 4.3-1: Force triangle for helical gearing. Schematic illustration, not to scale. Source: Calculation method for this learning unit (M=150 Nm, d=80 mm, β=12°, αn=20°)
Description and values of the figure

Three force components act at the point of tooth engagement: the circumferential force F_t= 2M/d, the axial force F_a=F_t·tan β (resulting from the helix angle β), and the radial force F_r=F_t·tan αn/cos β. For the worked example with M = 150 Nm, d = 80 mm, β = 12°, and αn = 20°, the results are F_t=3,750 N, F_a≈ 797 N (approximately 21% of F_t), and F_r≈1,395 N (approximately 37% of F_t).

Forces in the worked example (M=150 Nm, d=80 mm, β=12°, αn=20°)
Force Formula Value
Umfangskraft F_t2 · M/d3,750 N
Axial force F_aF_t · tan β≈ 797 N
Radial force F_rF_t · tan αn / cos β≈ 1,395 N

Knowledge check

Answer all three questions, then click "Check". From 2 of 3 correct answers, the unit counts as completed. You can retry at any time.

This feature needs JavaScript. You can still read the learning content without JavaScript.

Question 1 of 3: What forces does helical gearing generate in addition to the circumferential and radial forces?
Explanation

The inclined tooth line generates an axial force F_a = F_t · tan β, which the shaft bearings must additionally support.

Source: Helical Gearing vs. Spur Gearing →
Question 2 of 3: As a rule of thumb: by what maximum percentage does helical gearing have a higher load-carrying capacity than geometrically comparable spur gearing?
%
Explanation

Helical spur gears have up to about 30% higher load-carrying capacity than comparable straight-toothed gears—due to the higher overall overlap, more teeth are in contact at the same time on average.

Source: Helical Gearing vs. Spur Gearing →
Question 3 of 3: Which design completely cancels out the axial force of helical gearing?
Explanation

Arrow-tooth gearing combines two mirror-image helical-toothed halves on a single gear—the axial forces of the two halves cancel each other out.

Source: Helical Gearing vs. Spur Gearing →

Please answer all three questions to activate "Check".

Further reading (optional)

Guide: Helical Gearing vs. Spur Gearing (opens in a new tab) Online Assistant: Gear Type Wizard (opens in a new tab)

Learning purpose: calculation methods and figures are simplified teaching examples. For a real machine, the manufacturer’s specifications, the relevant standards and a check by a qualified person apply.

Curriculum v0.1 (Beta) · Status 17.09.2026 · content carefully prepared and reviewed – final sign-off to follow

+49 [40] 5388921-11 sales@tea-hamburg.de