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MODULE 7 · UNIT 1 OF 5

Coupling Types and Selection

approx. 7 min · Learning goals, example, knowledge check

Learning goals — after this unit, you will be able to …

  • Distinguish between rigid, torsionally flexible, torsionally rigid, and engageable couplings according to VDI 2240;
  • Calculate the rated torque of a coupling based on power and speed, and size it using a service factor;
  • Select a coupling based on torque, misalignment tolerance, speed, and zero backlash.

Overview of Coupling Types

Couplings connect two shafts, transmit torque, and compensate for manufacturing and assembly tolerances. VDI 2240 systematically classifies them into non-switchable and switchable couplings. Among non-switchable couplings, a distinction is made between rigid couplings (e.g., flange couplings per DIN 116, with no backlash or elasticity but with full alignment accuracy), torsionally flexible couplings (e.g., jaw couplings with an elastomer star, which compensate for radial, axial, and angular misalignment and dampen vibrations), and torsionally rigid, compensating couplings (e.g., metal bellows couplings, which combine high stiffness with precision). Among engageable couplings, a distinction is made between externally actuated (e.g., electromagnetic couplings) and self-acting types (e.g., freewheel, slip, or safety couplings); they connect or disconnect the shafts—either externally actuated or self-acting (depending on direction, speed, or torque).

Rated Torque and Service Factor

A coupling is selected based on the torque to be transmitted. The rated torque is derived from power and speed and is then multiplied by an operating or shock factor (S_B), which accounts for load peaks, start-ups, and shocks. For flexible shaft couplings, DIN 740 specifies the design procedure and the service factors:

M_N = 9550 · P / n

M_dim = M_N · S_B

M_N = Rated torque (Nm) · P = Power (kW) · n = Speed (min⁻¹) · S_B = Service factor (guideline values: smooth operation 1.0–1.5 · moderate shocks 1.5–2.5 · severe shocks 2.5–4.0)

Five selection criteria

  • Torque: Design for a value ranging from 1.3 to 1.5 times the continuous drive torque.
  • Alignment tolerances: radial 0.1–1.0 mm, axial 0.2–2.0 mm, angular 0.5–2.0°.
  • Speed/Centrifugal Forces: Centrifugal forces become a factor at speeds of >5,000 min⁻¹—lightweight, compact designs are preferred.
  • Zero backlash: specified in arcminutes (arcmin); 1° = 60 arcmin.
  • Temperature range: Elastomer couplings typically range from −20 to +80 °C; for higher temperatures, metal bellows or flange couplings are used.

Mnemonic

A coupling is not selected based on the rated torque alone: the service factor, misalignment tolerance, and the required zero backlash in arc minutes are at least as important in determining which coupling type is suitable.

Worked example

Given

A motor has a power output of P = 5.5 kW at n = 1,450 min⁻¹; the application involves moderate shocks (S_B = 2.0).

Calculation

  • M_N = 9550 · 5.5 / 1,450 ≈ 36.2 Nm
  • M_dim = 36.2 · 2.0 ≈ 72.4 Nm → the coupling must be rated for at least ~72 Nm
  • Marked point: Example: 72.4 Nm
  • Marked point 1: Example: 72.4 Nm
Figure 7.1-1: Design torque based on the shock factor. Source: Calculation method for this learning unit (content b: formula order corrected)
Description and values of the figure

The design moment M_dim=M_N·S_B increases linearly with the shock factor S_B. The three zones (different patterns rather than just colors) indicate the duty type: steady-state (S_B 1.0–1.5), moderate shocks (1.5–2.5), and severe shocks (2.5–4.0). The worked example with P =5.5 kW and n =1,450 min⁻¹ yields a rated torque of M_N≈36.2 Nm, and with S_B=2.0, a design torque of approximately 72.4 Nm.

M_dim S_B per shock factor
Shock factor S_BM_dim (Nm)
1.0 36.2
1.5 54.3
2.0 72.4
2.5 90.6
3.0 108.7
4.0 144.9

Knowledge check

Answer all three questions, then click "Check". From 2 of 3 correct answers, the unit counts as completed. You can retry at any time.

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Question 1 of 3: A motor has a power output of P = 7.5 kW at n = 1,000 min⁻¹. What is the rated torque M_N in Nm?
Nm
Explanation

M_N = 9550 · P / n = 9550 · 7.5 / 1,000 ≈ 71.6 Nm.

Source: Couplings in Mechanical Engineering →
Question 2 of 3: According to which standard are service factors for flexible (elastic) shaft couplings sized?
Explanation

DIN 740 specifies the design procedure and service factors for flexible shaft couplings. DIN 116, on the other hand, applies to rigid flange couplings (disc couplings).

Source: Couplings in Mechanical Engineering →
Question 3 of 3: What is the typical torsional backlash for a bellows coupling?
Explanation

Bellows couplings achieve a torsional backlash of less than 1 arcminute (arcmin) and are thus the standard for backlash-free, precise torque transmission in robotics and positioning drives.

Source: Couplings in Mechanical Engineering →

Please answer all three questions to activate "Check".

Further reading (optional)

Guide: Couplings in Mechanical Engineering (opens in a new tab)

Learning purpose: calculation methods and figures are simplified teaching examples. For a real machine, the manufacturer’s specifications, the relevant standards and a check by a qualified person apply.

Curriculum v0.1 (Beta) · Status 17.09.2026 · content carefully prepared and reviewed – final sign-off to follow

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