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MODULE 8 OF 8

Lubrication, Maintenance, and Total Cost

From lubricant selection to total cost of ownership: determining whether to use grease or oil, calculating relubrication intervals, maintaining roller guides, and assessing the total cost of ownership (TCO) of a drive train.

5 units · approx. 36 minutes total · Step 1 of 7

Getting Started

This module covers lubrication, maintenance, and the total cost of ownership of a drive train—from choosing between grease and oil to selecting the appropriate viscosity grade and calculating relubrication intervals for rolling bearings. You will learn how the dn value, temperature, load, and environment affect lubrication intervals, and what a structured maintenance plan for roller guides looks like.

The course concludes with a discussion of the total cost of ownership: why, in continuous operation, it is efficiency—rather than the purchase price—that determines the costs—and what this means for procurement and supplier consolidation. Calculation exercises on relubrication intervals and the total cost of ownership, eight flashcards, a case study from the procurement department, and a self-test at the end bring the theory to life.

Learning Objectives – After completing this module, you will be able to:

  • determine the appropriate choice between grease and oil for a given application based on speed (dn value), temperature, and sealing;
  • roughly classify the appropriate ISO VG viscosity grade for gearboxes and rolling bearings;
  • Calculate a relubrication interval for a grease-lubricated rolling bearing using the approximate formula;
  • create a maintenance and lubrication schedule for roller guides and avoid typical lubrication errors;
  • Classify the TCO cost categories of a powertrain and the cost categories of a procurement beyond the unit price.

Learning units

Five short learning units (6–8 minutes) with learning objectives, examples, and knowledge checks—standalone learning content for this module, maintained independently of the website’s guides. Progress is saved locally in this browser.

Calculation Exercise 1: Relubrication Interval

A deep groove ball bearing 6309 (bore diameter d = 45 mm) operates at n = 1,800 min⁻¹. According to the approximation formula from the guide, the basic interval (without correction factors) is t_grund ≈ 9,790 operating hours. The load and operating environment are not critical (f_L = f_U = 1.0), but the bearing temperature is around 85 °C (f_T = 0.5).

Calculate the relubrication interval t_f in operating hours and the calendar time in years for operation at 2,080 hours per year (8 h/day, 5 days/week).

For further reading: Calculating relubrication intervals (opens in a new tab)

Calculation Exercise 2: Total Cost of Ownership (TCO)

A drive delivers 11 kW of mechanical output power at 6,000 operating hours per year, either with a worm gearbox (η = 70 %) or a planetary gearbox (η = 96 %)—using the same IE3 motor (η ≈ 91.4%, assumed to be the same for both variants for simplicity; in reality, the worm gearbox variant requires a larger motor). In the example provided in this learning unit, the annual energy consumption is 103,157 kWh with the worm gearbox and 75,219 kWh with the planetary gearbox.

Calculate (a) by what percentage the energy consumption of the worm gearbox is higher, and (b) the resulting additional CO₂ emissions in metric tons over 10 years (emission factor 0.344 kg CO₂/kWh, German electricity mix in 2025, Federal Environment Agency).

Calculate the total cost of ownership for procurement yourself: Procurement Cost Calculator (opens in a new tab)

Flashcards: Lubrication and Maintenance Terms

Eight technical terms from the glossary—click on the card (or press Enter or the spacebar) to see the definition.

Flashcards

Tap to see the definition.

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Tribology
The science of friction, wear, and lubrication on surfaces in relative motion—the scientific basis for selecting lubricants, surface coatings, and bearing designs. Source: Glossary “Tribology”
L10 service life
The L10 service life is the nominal service life (in kilometers of travel) that at least 90% of all guides in a series achieve without material fatigue. It relates the dynamic load rating C to the equivalent operating load P and is the standard parameter for the service life design of linear guides and rolling bearings. Source: Glossary “L10 service life”
Pitting
Pitting refers to small, shell-shaped indentations on the tooth flank caused by rolling fatigue. This is caused by excessive Hertzian contact pressure, which, due to alternating compressive and tensile stresses beneath the surface, ultimately leads to cracking and material spalling. Source: Glossary “Pitting”
Dynamic load rating
The dynamic load rating C is the load at which a guide or bearing series achieves a defined nominal service life (typically 100 km of travel). It is the key parameter in the L10 service life calculation: The higher the C value, the longer the service life at a given operating load. Source: Glossary “Dynamic load rating”
Rolling element
Rolling elements are the components that roll between two raceways in guides and bearings. They transmit the load and minimize friction. Balls provide point contact for high speeds; rollers provide line contact for higher load-carrying capacity. Source: Glossary “Rolling element”
Line contact
In line contact, a cylindrical roller contacts the raceway along a straight line rather than at a single point. The load is distributed over a larger area—resulting in higher load-carrying capacity, lower contact pressure, and greater stiffness compared to the point contact of a ball. Source: Glossary “Line contact”
Roller recirculation
In a roller recirculation system, the rolling elements circulate in a closed path within the carriage. This design allows for a theoretically unlimited travel distance—in contrast to non-circulating guides (e.g., crossed-roller guides), where the stroke is limited by the cage length. Source: Glossary “Roller recirculation”
Cage positive guidance
Cage positive guidance is a mechanical method of synchronizing the rolling element cage—typically via a rack and pinion. It prevents unwanted cage movement, which can occur particularly under high dynamic loads, vibrations, or frequent changes in direction. Source: Glossary “Cage positive guidance”

Case Study: Purchasing Asks—Is There a Cheaper Supplier?

A customer operates a pump with a mechanical output of 11 kW in continuous operation (6,000 operating hours per year), with a planned service life of 10 Jahre. Currently, a planetary gearbox is installed. The purchasing department has received a significantly lower quote for a worm gearbox from a new supplier and would like to switch to this supplier based solely on the lower purchase price.

Key Questions

  1. Given this operating profile, what percentage of the total cost of ownership (TCO) does the purchase price typically account for, and what percentage is accounted for by energy costs?
  2. How does the annual energy consumption change if a worm gearbox (η = 70%) is used instead of a planetary gearbox (η = 96%)?
  3. What would you recommend to the purchasing department—and what information is still needed to make a fully informed decision?
View Worked Solution

1. In continuous operation, the purchase price typically accounts for only a fraction of the TCO (guideline: components 3–8%, approximately 5–12% including installation), whereas energy costs account for 70–90%. With this operating profile, a lower purchase price says very little about the total cost of ownership.

2. In the example provided in this learning unit (IE3 motor, 11 kW, η ≈ 91.4 %, 6,000 h/year), the worm gearbox consumes about 37% more electrical energy per year than the planetary gearbox (103,157 kWh instead of 75,219 kWh) and emits about 96 metric tons more CO₂ (355 t instead of 259 t, emission factor 0.344 kg CO₂/kWh, German electricity mix in 2025). For simplicity, motor efficiency is assumed to be the same for both variants (IE3, 91.4 %); in reality, the worm gear variant requires a larger motor.

3. Recommendation: Compare the total cost of ownership (TCO) over the planned service life rather than just the purchase price—the difference in efficiency generally far outweighs the initial cost advantage of a worm gearbox in continuous operation. Missing information: the actual operating hours per year, the load profile (continuous operation or only occasional use), and whether self-locking is required at all—in which case a worm gearbox could still be the right choice despite the energy costs. A simple unit price comparison overlooks the largest cost factor.

Technical basis exclusively: Calculating TCO in the powertrain (opens in a new tab)

Self-test

10 questions about this module—immediate feedback with explanations and source links. The module is considered complete if you score 7 out of 10 points or higher.

Self-test

10 questions for this module. You see right after each answer whether it was correct.

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Before each answer, you state how confident you feel. This helps distinguish knowledge gaps from uncertainty. It has no effect on the score.

Question 1 of 10

Question 1 of 10

According to the worked example in this learning unit, a rolling bearing with a bore diameter of d = 50 mm rotates at n = 9,000 rpm. What is the resulting dn value, and what type of lubrication is recommended?

Explanation

dn = d × n = 50 × 9,000 = 450,000 – this is significantly above the limit of dn ≈ 300,000, beyond which, according to the learning unit, a switch to oil lubrication should be made because grease does not dissipate the generated heat effectively.

Source: Greases vs. Lubricating Oils: A Decision-Making Guide →
Question 2 of 10

What does the learning unit recommend when both high speed and high thermal load are present?

Explanation

Although grease provides good sealing, it does not cool well. According to the learning unit, when both high speed and high thermal load are required, oil generally outperforms grease because it can dissipate the heat generated by friction.

Source: Greases vs. Lubricating Oils: A Decision-Making Guide →
Question 3 of 10

According to the learning unit, how is the dynamic viscosity η related to the kinematic viscosity ν?

Explanation

The dynamic viscosity η is the absolute flow resistance: η = ν × ρ. In mechanical engineering, however, the kinematic viscosity ν (mm²/s at 40 °C) is the commonly used reference value.

Source: Viscosity: Choosing the Right Class →
Question 4 of 10

What ISO VG class does the learning unit recommend as a rule of thumb for rolling bearings at high speeds (dn > 300,000)?

Explanation

The rule of thumb for speed is: High speed (dn > 300,000) → ISO VG 10–32; Medium speed (dn 100,000–300,000) → ISO VG 32–68; Low speed (dn < 100,000) → ISO VG 100–220.

Source: Viscosity: Choosing the Right Class →
Question 5 of 10

According to the approximation formula in this learning unit, which variables are used multiplicatively as correction factors in the relubrication interval t_f?

Explanation

t_f = k_f × (14·10⁶ / (n × √d) − 4 × d) × f_T × f_L × f_U – the three correction factors f_T, f_L, f_U represent temperature, load, and environment; the closer the values are to 1.0, the more favorable the conditions.

Source: Calculating Relubrication Intervals: Formulas and Practical Examples →
Question 6 of 10

According to the learning unit, a deep groove ball bearing 6309 (d = 45 mm) has a basic service life of t_grund ≈ 9,790 operating hours. At a bearing temperature of approximately 85 °C, f_T = 0.5; the load and ambient conditions are non-critical (f_L = f_U = 1.0). What is the relubrication interval t_f in operating hours?

Operating hours
Explanation

t_f ="t_grund" × "f_T" × "f_L" × "f_U" = "9,790" × "0.5" × "1.0" × "1.0" ≈ "4,900" operating hours—equivalent to approximately "2.4" years at "2,080" operating hours per year.

Source: Calculating Relubrication Intervals: Formulas and Practical Examples →
Question 7 of 10

According to the learning unit, up to what travel speed is grease the first choice for roller guides before switching to oil or recirculating lubrication?

Explanation

Grease remains the first choice for travel speeds up to about 2–3 m/s—above that, or when there is high heat generation, the system switches to oil or recirculating lubrication.

Source: Roller Guide Maintenance & Lubrication →
Question 8 of 10

According to the learning unit, which factors influence the relubrication interval of a roller guide? (Multiple choice)

Explanation

The service life depends on four factors: load, speed, temperature, and environment (contamination/humidity)—the color of the packaging has no technical significance.

Source: Roller Guide Maintenance & Lubrication →
Question 9 of 10

According to the rule of thumb in this learning unit, how much does preventive maintenance cost per year?

Explanation

As a rule of thumb, preventive maintenance costs about 1–2% of the purchase price per year—a small expense that prevents costly consequential damage.

Source: Calculating TCO in the Powertrain →
Question 10 of 10

A worm gearbox (η = 70%) and a planetary gearbox (η = 96%) deliver the same mechanical output power when driven by the same IE3 motor. By what percentage is the electrical power consumption (and thus the energy costs) higher for the worm gearbox compared to the planetary gearbox?

%
Explanation

Electric power consumption is inversely proportional to the total efficiency of the motor and gearbox. In the example given in this learning unit (IE3 motor, 11 kW; η ≈ 91.4%; 6,000 h/year), this corresponds to 103,157 kWh instead of 75,219 kWh per year—approximately 37% more. For simplicity, the motor efficiency is assumed to be the same for both variants (IE3, 91.4%); in reality, the worm gear variant requires a larger motor.

Source: Calculating TCO in the Powertrain →

Advanced Topics (optional)

The six guide articles in this module, in case you’d like to delve deeper. Reading them is not required for the learning units and self-test in this module.

Curriculum v0.1 (Beta) · As of 17.09.2026 · content carefully prepared and reviewed – final sign-off to follow

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